Doctor Who - The End Of Time: Part II

Doctor Who - The End Of Time: Part II
Doctor Who - The End Of Time: Part II
Doctor Who - The End Of Time: Part II
Doctor Who - The End Of Time: Part II
Doctor Who - The End Of Time: Part II
Doctor Who - The End Of Time: Part II
Doctor Who - The End Of Time: Part II
Doctor Who - The End Of Time: Part II
Doctor Who - The End Of Time: Part II

Doctor Who - The End of Time: Part II

More Posts from Takinbreak and Others

1 year ago
Visualization Of The Rubik's Cube

Visualization of the Rubik's cube

1 year ago

crowley. crowley’s new hair color is 6.66. That’s the color coding. his hair is literally demonic. i love this show

Crowley. Crowley’s New Hair Color Is 6.66. That’s The Color Coding. His Hair Is Literally Demonic.
Crowley. Crowley’s New Hair Color Is 6.66. That’s The Color Coding. His Hair Is Literally Demonic.
1 year ago

i just realised there are people out there who don't know about proof by mathematical induction. the world is a dark dark place

1 year ago
Sketchbook
Sketchbook

sketchbook

9 months ago

Reblog if you ARE a woman in STEM, SUPPORT women in STEM, or ARE STILL BITTER about Rosalind Franklin not getting credit for discovering the structure of DNA and the Nobel prize going to Watson and Crick instead.

1 year ago
5x5 Diamond Rule, Iterates 1-32

5x5 Diamond rule, iterates 1-32

5x5 Diamond Rule, Iterates 1-32
5x5 Diamond Rule, Iterates 1-32
5x5 Diamond Rule, Iterates 1-32

Iterates 40, 48, 56

5x5 Diamond Rule, Iterates 1-32

Iterate 64

5x5 Diamond Rule, Iterates 1-32

Iterate 128

This is a 2D cellular automaton generating a 3D fractal layer by layer. I coded it in Microsoft Excel - each pixel is 1 cell.

See more MSExcel fractals

1 year ago

"Is maths really necessary?" Yes, yes it is

1 year ago

I was dicking around in polar coordinates last night and I found something... extensible.

I Was Dicking Around In Polar Coordinates Last Night And I Found Something... Extensible.

r = sqrt(sec(2θ)), an ordinary hyperbola. One of the five conic sections. In Cartesian coordinates x^2 = y^2 + 1.

I Was Dicking Around In Polar Coordinates Last Night And I Found Something... Extensible.

r = sqrt(sec(3θ)), a triperbola :)

And now here's r = sqrt(sec(aθ)) for some other values of a:

I Was Dicking Around In Polar Coordinates Last Night And I Found Something... Extensible.
I Was Dicking Around In Polar Coordinates Last Night And I Found Something... Extensible.
I Was Dicking Around In Polar Coordinates Last Night And I Found Something... Extensible.
I Was Dicking Around In Polar Coordinates Last Night And I Found Something... Extensible.
I Was Dicking Around In Polar Coordinates Last Night And I Found Something... Extensible.
I Was Dicking Around In Polar Coordinates Last Night And I Found Something... Extensible.

a = [1/2 2/7 6/1 5/2 3/5 5/9]

1 year ago

what the fuck is morbius even about

1 year ago
Happy Angel Crowley Today 🥹

happy Angel Crowley today 🥹

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takinbreak - takinbreak
takinbreak

david tennant is my dad

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